Surface
temperature ['K] = ( (1 / (Orbital radius [km] * 8E-14) ^ 0.5 ) *
(luminosity [sols]) ^ 0.5 )
This is a very rough and ready
approximation, but should be accurate to within about 10'K, of course
this equation does not count for atmospheres, or slowly rotating planet
heat side differences etc. it is best used as an approximate guide. It
is basically derived from the inverse square relationship between
insolation and distance, you can refine the constant to give better
results (back)
Tides
This simple equation provides fairly
accurate results from tides generated by any body on any other body, it
is simply an extension of the forces between two bodies
Tide Height [m] = ( ( m*(R^4)) / (M*(R^3)
) )
where m is the remote mass in kg
where R is the distance between the two
bodies in metres
where M is the central mass in kg (back)
Barycentre
calculation
The barycentre is the centre of mass
between two bodies.
s = ( ( m * R ) / ( M + m ) )
s is the distance of the barycentre from
the central mass [m]
m is the satellite mass [kg]
M is the central mass [kg]
R is the radius between the two bodies
(from their centres) [m] (back)
Orbital Information
Period
Period Time [s] =((4*(pi^2)*(R^3))/(G*M));
G = constant (6.673E-11)
R = orbital radius (m)
M = central mass (kg)
This formula assumes for circular orbits,
but as Kepler tells us that the angular velocity remains constant, and
so provide quite accurate results (less than 0.1% error). (back)
Eccentricity
Using the eccentricity system that runs
between 0 and 1, where 0 is a perfect circular orbit.
A = R*(1+E)
P = R*(1-E)
where
E = eccentricity, unit-less number
A = Apoapsis distance (most distant)
P = Periapsis distance (closest
approach)
The actual distance units are
irrelevant as long as the original units are maintained, metres, km,
etc.
Most planets have low eccentricities
generally below 0.1, Earth's own eccentricity is about 0.016. Comets
can have eccentricities of up to 0.3. (back)
Complete Basics:
Diameter is of course twice the radius.
Volume of a
sphere (can be assumed for planets stars etc.)
Volume = (4/3)*Pi*radius^3 (back)
To work out mass of such sphere you need
to know the density if you are using g/cm^3 then
Mass = Volume * Density
*1000
Which will give you a mass in kg, as long
as volume is in metres cubed, if you want metric tonnes, you can
disregard the *1000 as long as volume is still in metres cubed. (back)
Notes
Stars
Multiple
star systems
These
type of systems with more than one sun are unlikely to have a great
many planets around them, nor are they readily able to form due to the
complicated gravitational fields caused by the large masses of the
stars in the system.
But
stars orbiting each other at great distances, in excess of a few
thousand million km may be able to have relatively normal independent
planetary systems. Stars closer than this cause far too much chaos for
the development of ‘normal’ planetary systems, there will be few
planets, if any.
It
may be possible for planets to follow a ‘figure of eight’ between
two parent stars, but this kind of orbit is precarious state, with the
result of the planet eventually coming to reside around one star, (in
a very eccentric orbit perhaps), or the destruction of the planet by
falling inwards or being catapulted out of the system. (back)